How to trim spaces, new line and return line characters in Go language?

I have answered this in StackOverflow too.
Please visit the answer.

Here is the solutions:

	package main
	import (
	"fmt"
	strings "strings"
	)
	func main() {
	test := "\t pdftk 2.0.2 \n"
	result := strings.TrimSpace(test)
	fmt.Printf("Length of %q is %d\n", test, len(test))
	fmt.Printf("Length of %q is %d\n\n", result, len(result))
	test = "\n\r pdftk 2.0.2 \n\r"
	result = strings.TrimSpace(test)
	fmt.Printf("Length of %q is %d\n", test, len(test))
	fmt.Printf("Length of %q is %d\n\n", result, len(result))
	test = "\n\r\n\r pdftk 2.0.2 \n\r\n\r"
	result = strings.TrimSpace(test)
	fmt.Printf("Length of %q is %d\n", test, len(test))
	fmt.Printf("Length of %q is %d\n\n", result, len(result))
	test = "\r pdftk 2.0.2 \r"
	result = strings.TrimSpace(test)
	fmt.Printf("Length of %q is %d\n", test, len(test))
	fmt.Printf("Length of %q is %d\n\n", result, len(result))
	test := "pdftk 2.02 a Handy Tool for Manipulating PDF Documents\nCopyright (c) 2003-13 Steward and Lee, LLC - Please Visit: www.pdftk.com\nThis is free software; see the source code for copying conditions. There is\nNO warranty, not even for MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE."
	fmt.Println(test)
	strArray := strings.Split(test, "\n")
	fmt.Println(strArray)
	result = strings.Replace(test, "\n", " ", -1)
	fmt.Println(result)
	}

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